Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

3N2H4 (l) →4NH3 (g) + N2 (g)

A.) 2.0 mol N2H4

Question

Chemistry

Guest

3 September, 11:20

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

3N2H4 (l) →4NH3 (g) + N2 (g)

A.) 2.0 mol N2H4

+2

Answers (1)

Know the Answer?

Lawson Fleming · Answer 1

1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4 (l) →4NH3 (g) + N2 (g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

Answer: 2.7 mol

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:3N2H4 (l) →4NH3 (g) + N2 (g)A.) 2.0 mol N2H4

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

3N2H4 (l) →4NH3 (g) + N2 (g)

A.) 2.0 mol N2H4