How many grams of CuO would be required to produce 10.0 moles of

nitrogen gas in the following chemical reaction?

2 NH3 (g) + 3 CuO (s) 3 Cu (s) + N2 (g) + 3 H2O (g)

2390 CuO

Explanation:

2 NH3 (g) + 3 CuO (s) - --> 3 Cu (s) + N2 (g) + 3 H2O (g)

from reaction 3 mol 1 mol

given x mol 10.0 mol

x = 3*10.0/1 = 30.0 mol

M (CuO) = 63.5 + 16.0 = 79.5 g/mol

m (CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO