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3 September, 11:27

How many grams of CuO would be required to produce 10.0 moles of

nitrogen gas in the following chemical reaction?

2 NH3 (g) + 3 CuO (s) 3 Cu (s) + N2 (g) + 3 H2O (g)

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  1. 3 September, 14:10
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    2390 CuO

    Explanation:

    2 NH3 (g) + 3 CuO (s) - --> 3 Cu (s) + N2 (g) + 3 H2O (g)

    from reaction 3 mol 1 mol

    given x mol 10.0 mol

    x = 3*10.0/1 = 30.0 mol

    M (CuO) = 63.5 + 16.0 = 79.5 g/mol

    m (CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO
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