What mass of h2so4 would be required to react with 0.75 mol of naoh? what mass of each product if formed by this reaction?

1) State the balanced chemical reaction

H2SO4 + 2NaOH - > Na2SO4 + 2H2O

2) State the molar ratios:

1 mol H2SO4 : 2 mol NaOH

3) Set the proportions using the number of moles of one rectant and x for the unknown one>

1 mol H2SO4 / 2 mol NaOH = x mol H2SO4 / 0.75 mol NaOH

=> x = 0.75 mol NaOH * [1 mol H2SO4 / 2 mol NaOH]

x = 0.375 mol H2SO4

4) Calculate the mass using the molar mass of H2SO4, MM.

MM = 2*1g/mol + 32.1 g/mol + 4*16 g/mol = 98.1 g/mol

mass = # of moles * molar mass = 0.375 mol * 98.1 g/mol = 36.79 g.

Answer: 36.8 grams