A 100 gram sample of H2O at 22.0 celsius absorbs 8360 joules of heat. what will be the final temperature of the water?

In this problem you need to use the equation q=mcΔT. q is the amount of heat absorbed or released, m is the mass of what ever the q value is referring to, delta T is the temperature change, and c is the specific heat capacity of what ever q is referring to. With that equation you can rewrite it as T (final) = (q/mc) + T (intital). In the question that you gave, m=100g, T (initial) = 22.0°C, q=8360J, and c=4.179J/g°C. when you plug everything in T (final) should equal 41.9°C.