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18 May, 10:49

A gas had a volume of 50L and a temperature of 650k. if the temperature increased to 2600k, what would be the volume be?

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Answers (2)
  1. 18 May, 12:52
    0
    Charles' Law: V1 = V2 V2 = V1T2 V2 = (50L) (2600K) = 200L

    T1 T2 T1 (650K)
  2. 18 May, 14:09
    0
    Assuming it's a perfect gas, we have PV=nRT hence V and T are proportional. T increased by 2600/650=4 times hence the volume will be 4 times bigger, which is 200L
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