To titrate 15.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the molarity of the HCl

Using Formula M1V1=M2V2

HCl+NaOH - > NaCl + H2O

1:1 ratio

M1=Molarity of HCl = X

V1 = Volume of HCl = 15mL = 0.015L

M2 = Molarity of NaOH = 0.2M

V2 = Volume of NaOh = 25mL = 0.025L

(XM) (0.015L) = (0.2M) (0.025L)

Isolate unknown:

(XM) = [ (0.2M) (0.025L) / (0.015L) ]

XM=0.33M

Hence, Molarity of HCl is = 0.33 Moles