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8 November, 04:29

Compare the rates of effusion of nh3 and o2

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  1. 8 November, 08:01
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    According the Graham's Law of effusion, if we let M₁ and R₁ be the mass and effusion rate of NH₃ and M₂ and R₂ be the mass and effusion rate of O₂, then:

    R₂/R₁ = √ (M₁/M₂).

    Since M₁ = 14.01 + 3*1.01 = 17.04 and M₂ = 16 * 2 = 32, we see that:

    R₂/R₁ = √ (17.04/32) = 0.73

    ==> R₂ = 0.73 * R₁.

    Thus, O₂ effuses at 73% the speed that NH₃ does
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