Studying and going over my wrong answers so I can do well on finals ...

Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is: Ch4 (g) + 2O2 (g) - - - > 2H2O (l)

CH4+2O2 gives 2H2O+CO2

so for every mole of ch4 we produce 1 mole co2

since the molecular weight of ch4 is 16 we can divide 50.6 by 16 to find the number of moles for ch4 which is 3.16. we already know for each mole of ch4 we have one mole of co2. so for 3.16 mole of ch4 we produce 3.16 mole of co2. 1 mole of co2 is 44gram. so 3.16 mole would be 139.15 gram.