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30 August, 20:41

How many bromine atoms are present in 39.9 g of CH2Br2

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  1. 30 August, 21:48
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    Molar mass of CH2Br2: 173.83 g/mol

    Given: 39.9 g / 173.83 g/mol = 0.230 mol

    0.230 mol x 6.022x10^23 atoms/mol =

    1.39 x 10^23 atoms
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