Hydrogen sulfide gas and sulfur dioxide gas react to form solid sulfur and water. If 10.0g of gaseous hydrogen sulphide is mixed with 10.0g of gaseous sulfur dioxide, how many grams of solid sulfur can form?

The reaction equation:

2H₂S + SO₂ → 3S + 2H₂O

Calculating moles of H₂S:

10 / 34 = 0.29

Moles of SO₂:

10 / 64 = 0.15

Stoichometric amounts of each reactant are present so the moles of S formed will be:

0.15 x 3 = 0.45

Mass of S formed = 14.4 grams