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26 April, 14:22

Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for this gas? express your answer as a chemical formula.

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  1. 26 April, 18:07
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    Assuming we have 100 g of sample

    30.45/MW of N 14g = 2.175

    69.55/MW of O 16g = 4.34

    4.34/2.185 = 2

    for every 1 mole of N we have 2 moles of O

    so the empirical formula would be NO2

    without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question
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