A gas mixture contains each of the following gases at the indicated partial pressures:, 221O2torr, N2,131 torr; and He 131 torr

What mass of each gas is present in a 1.30 - L sample of this mixture at 25.0 degrees C?

221 torr + 131 torr + 131 torr = 483 torr total

n = PV / RT = (483 torr) x (1.30 L) / ((62.36367 L Torr/K mol) x (25.0 + 273.15 K)) = 0.033769 mol gases total

(0.033769 mol) x (221 torr N2 / 483 torr) x (28.01344 g N2/mol) = 0.433 g N2

(0.033769 mol) x (131 torr O2 / 483 torr) x (31.99886 g O2/mol) = 0.293 g O2

(0.033769 mol) x (131 torr He / 483 torr) x (4.0026 g He/mol) = 0.0367 g He