Darin skateboarded to the north at 7 m/s. In 5 seconds, he slowed down to 6 m/s. What was his acceleration?

A. 0.2 m/s2 north

B.-0.2 m/s2 north

C. 5 m/s2 north

D.-5 m/s2 north

Question

Guest

15 March, 10:00

+5

Answers (2)

Know the Answer?

Good · Answer 1

(v-u) / t

= (6-7) / 5

=-1/5

=-.2m/s2

so the answer is B!

Aspen Oconnor · Answer 2

Initial velocity (u) = 7m/s

time (t) = 5 seconds

final velocity (v) = 6m/s

a=v-u/t

=6-7/5

= - 1/5

= - 0.2m/s2 north

Darin skateboarded to the north at 7 m/s. In 5 seconds, he slowed down to 6 m/s. What was his acceleration?A. 0.2 m/s2 northB.-0.2 m/s2 northC. 5 m/s2 northD.-5 m/s2 north