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15 March, 10:00

Darin skateboarded to the north at 7 m/s. In 5 seconds, he slowed down to 6 m/s. What was his acceleration?

A. 0.2 m/s2 north

B.-0.2 m/s2 north

C. 5 m/s2 north

D.-5 m/s2 north

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Answers (2)
  1. 15 March, 11:12
    0
    (v-u) / t

    = (6-7) / 5

    =-1/5

    =-.2m/s2

    so the answer is B!
  2. 15 March, 13:47
    0
    Initial velocity (u) = 7m/s

    time (t) = 5 seconds

    final velocity (v) = 6m/s

    a=v-u/t

    =6-7/5

    = - 1/5

    = - 0.2m/s2 north
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