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30 November, 18:28

How many moles of Fe2O3 are in 209 g of the compound?

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  1. 30 November, 19:59
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    M = 209g

    M = 56 * 2 + 16 * 3 = 160 g/mol

    n = m/M = 209g / 160 g/mol = 1,30625mol
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