Which equivalence factor set should you use to convert from 4.23 x 10^12 atoms of Ca to grams of Ca?

(1 mol Ca/6.02 x 10^23 atoms Ca) (40.08 g Ca/1 mol Ca)

(1 mol Ca/4.23 x 10^12 atoms Ca) (40.08 g Ca/1 mol Ca)

(4.23 x 10^12 atoms Ca/1 mol Ca) (1 mol Ca/40.08 g Ca)

(4.23 x 10^12 atoms Ca/6.02 x 1023 atoms Ca) (40.08 g Ca)

Question

Chemistry

Trace

6 April, 23:26

Which equivalence factor set should you use to convert from 4.23 x 10^12 atoms of Ca to grams of Ca?

(1 mol Ca/6.02 x 10^23 atoms Ca) (40.08 g Ca/1 mol Ca)

(1 mol Ca/4.23 x 10^12 atoms Ca) (40.08 g Ca/1 mol Ca)

(4.23 x 10^12 atoms Ca/1 mol Ca) (1 mol Ca/40.08 g Ca)

(4.23 x 10^12 atoms Ca/6.02 x 1023 atoms Ca) (40.08 g Ca)

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Answers (1)

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Cassidy · Answer 1

The equivalence factor set is composed of the conversion factors that you use in order to convert one unit to another. In this case we are given with the number of atoms and wished to convert into grams. The equivalence factor set is composed of Avogadro's number and molar mass of Ca. The answer is