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4 January, 06:08

Calculate H3O + when OH - is 2*10 - 8

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  1. 4 January, 08:11
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    Relationship between [H3O+] and [OH-] is:

    [H3O+] X [OH-] = 1.00 X10^-14

    Rearranging gives:

    [H3O+] = 1.0X10^-14 / [OH-]

    Just plug in and calculate your [H3O+] values
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