Ask Question
1 January, 02:50

How many grams of KO2 are needed to form 8.0 g of O2?

+2
Answers (1)
  1. 1 January, 02:59
    0
    Using the atomic weights, K = 39, O=16 so KO2 = 39+32=71. So K=39/71 = 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2 = 9.76+8g=17.76.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many grams of KO2 are needed to form 8.0 g of O2? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers