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8 January, 21:47

A gas has a volume of 5.0 L at a pressure of 50 kPa. Solve for V2 when temperature is held constant and the pressure is increased to 125 kPa.

a. 12.5 L

b. 0.2 L

c. 2.0 L

d. 1250.0 L

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Answers (1)
  1. 8 January, 22:06
    0
    Given:

    P1 = 50 kPa

    V1 = 5.0 L

    P2 = 125 kPa

    V2 = ?

    Boyle's Law

    P1V1 = P2V2

    50 * 5 = 125 * V2

    250 = 125 * V2

    250 / 125 = V2

    2 = V2

    Answer is letter C. 2.0 L
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