How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this problem.

For this problem, we assume that ethane gas is an ideal gas so we can use the ideal gas equation which is expressed as:

PV = nRT

We first find the number of moles using the above equation.

n = PV / RT

n = (1.6 atm) (12.7 L) / (0.08206 L atm/mol K) (24 + 273.15 K)

n = 0.83 mol C2H6

M = 0.83 mol C2H6 (30.08 g / 1 mol) = 2.97 g C2H6