Write a program that reads in a list of numbers, and for each number, determines and prints out whether or not that number is abundant.

int IsAbundant (int n)

{

int divisorSum = 0;

for (int i = 1; i < n; i++) {

if ((n % i) = = 0) {

divisorSum + = i;

}

}

return divisorSum > n;

}

int main ()

{

int number = 0;

do {

printf ("Enter a number (0 to quit) : ");

scanf_s ("%d", &number);

if (IsAbundant (number)) {

printf ("%d is abundant!/n", number);

} else

{

printf ("%d is not abundant./n", number); }

} while (number > 0);

return 0;

}