Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in meters) is a 64-byte message? while electricity in the cable travels a bit slower than the speed of light, once you include delays in the electrical equipment in transmitting and receiving the signal, the eﬀective speed is only about 40 million meters per second. (hint: first calculate the number of seconds it would take to transmit the frame then calculate the number of meters the signal would travel in that time, and you have the total length of the frame.)

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Computers and Technology

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20 March, 14:06

Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in meters) is a 64-byte message? while electricity in the cable travels a bit slower than the speed of light, once you include delays in the electrical equipment in transmitting and receiving the signal, the eﬀective speed is only about 40 million meters per second. (hint: first calculate the number of seconds it would take to transmit the frame then calculate the number of meters the signal would travel in that time, and you have the total length of the frame.)

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Jackson · Answer 1

As we know that 10-bAse data travels at the rate of 10 mbps, therefore at 1 sec we have 10240 bytes.

We have to calculate for 64 bytes travelling in one second. Multiply both sides by 64.

64 sec = 10240 x 64 bytes

64 bytes = 64 / 10240 sec

Now we have to calculate for light of speed

1 sec = 186000 miles

Substitute this value to the formula above

64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles = 64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet

Therefore, 64 bytes is equal to 6138 x 10^3 feet long message