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12 December, 16:24

An incompressible fluid flows along a 0.20-m-diameter pipe with a uniform velocity of 3 m/s. If the pressure drop between the upstream and downstream sections of the pipe is 20 kPa, determine the power transferred to the fluid due to fluid normal stresses.

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  1. 12 December, 19:18
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    The power transferred to the fluid is 1.8852 kW

    Explanation:

    Power = pressure drop * area * velocity

    pressure drop = 20 kPa

    area = πd^2/4 = 3.142*0.2^2/4 = 0.03142 m^2

    velocity = 3 m/s

    Power = 20 * 0.03142 * 3 = 1.8852 kJ/s = 1.8852 kW
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