melinda is using a rectangular brass bar in a sculpture she is creating. the brass bar has a length that is 4 more than 3 times its width if the area of the rectangular brass bar is 480 inches what are the dimensions answer

The dimension of Length = L

The dimension of width = L

The dimension of Area = L²

Explanation:

A dimension is one of the physical properties that are regarded as fundamental measures of a physical quantity, such as mass, length and time.

L - length, W - width, A - Area

A = W * L (Formula for Area)

Given:

L = 4 + 3W (length that is 4 more than 3 times its width)

Area = 480 inches

A = W * L

Sub. Given into Formula of Area

480 = W (4 + 3W)

480 = 4W + 3W²

3W² + 4W - 480 = 0

a=3 b=4 c = - 480

where W = unknown using the quadratic equation

W = - b ± √ (b² - 4ac) / 2a

W = - 4 ± √ (4² - 4.3.-480) / 2.3

W = - 4 ± √ (16 + 5760) / 6

W = - 4 ± √ (5776) / 6

W = (-4 ± 76) / 6

W = (-4 + 76) / 6 or (-4-76) / 6

W = 72/6 or - 80/6

W = 12 or - 13.6

We choose w=12 inches

Sub. W into L

L = 4 + 3W

L = 4 + 3*12

L = 40 inches

Area = W * L

= 40 inches * 12 inches

Area = 480 inches ²

Dimension wise

The dimension of Length = L

The dimension of width = L

The dimension of Area = L²

180 x 60 inches

Width = 60 inches

Length = 180 inches

Explanation:

Given

Let L = Length

W = Width

P = Perimeter

Length = 3 * Width

L = 3W

Perimeter of Brass = 480 inches

P = 480

Perimeter is given as 2 (L + W);

So, 2 (L + W) = 480

L + W = 480/2

L + W = 240

Substitute 3W for L; so,

3W + W = 240

4W = 240

W = 240/4

W = 60 inches

L = 3W

L = 3 * 60

L = 180 inches