For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your depth of cut will be 0.105 in. The diameter of the workpiece is 1.00 in. a. Using a speed of 105 sfpm and a feed of 0.015, calculate the metal removal rate (MRR).

Question

Engineering

Matthews

23 April, 01:41

For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your depth of cut will be 0.105 in. The diameter of the workpiece is 1.00 in. a. Using a speed of 105 sfpm and a feed of 0.015, calculate the metal removal rate (MRR).

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Answers (1)

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Park · Answer 1

MRR = 1.984

Explanation:

Given that

Depth of cut, d=0.105 in

Diameter D = 1 in

Speed V = 105 sfpm

feed f = 0.015 ipr

Now the metal removal rate given as

MRR = 12 f V d

d = depth of cut

V = Speed

f=Feed

MRR = Metal removal rate

By putting the values

MRR = 12 f V d

MRR = 12 x 0.015 x 105 x 0.105

MRR = 1.984

Therefore answer is -

1.944