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13 March, 16:08

How much would a 10.0 inch long, 0.25 inch diameter AISI 1020 Q&T bolt stretch when loaded with 2000 lbs?

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  1. 13 March, 19:36
    0
    0.014 in

    Explanation:

    The Young's module of steel is of E = 210 GPa = 30*10^6 psi

    The section of the bolt would be:

    A = π/4 * D^2

    The stiffness would be:

    k = E * A / L

    k = π * D^2 * E / (4 * L)

    k = π * 0.25^2 * 30*10^6 / (4 * 10) = 147000 lb / in

    If I apply a force of 2000 lb, I calculate the stretching with Hooke's law:

    Δx = f / k

    Δx = 2000 / 147000 = 0.014 in
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