An insulated steady-flow mixing chamber has two inlets and 1 outlet. At inlet 1, the mass flow rate is 0.08 kg/s. At inlet 2, the mass flow rate is 0.15 kg/s. The average velocity at the outlet is 12.84 m/s. The area of the outlet is 0.01 m2. What is the specific volume of the outlet fluid (m3/kg) (3 significant figures) ?

the specific volume will be ρ = 1.791 kg/m³

Explanation:

From conservation of mass:

m₃ out = m₁ in + m₂ in

m₃ out = m₁ in + m₂ in = 0.08 kg/s + 0.15 kg/s = 0.23 kg/s

the volumetric flow rate q at the outlet will be

q = v*A, where v = velocity at the outlet and A = area of the outlet

q = 12.84 m/s * 0.01 m² = 0.1284 m³/s

the specific volume of the outlet fluid will be

ρ = m₃ out / q = 0.23 kg/s / 0.1284 m³/s = 1.791 kg/m³

ρ = 1.791 kg/m³