An average person produce 0.25 kg of moisture while taking a shower and 0.05 kg while bathing in a tub. Consider a family of four who each shower once a day in a bathroom that is not ventilated. Taking the heat of vaporization of water to be 2450 kJ/kg, determine the contribution of showers to the latent heat load of the air conditioner per day in summer?

Question

Engineering

Cervantes

23 October, 09:06

An average person produce 0.25 kg of moisture while taking a shower and 0.05 kg while bathing in a tub. Consider a family of four who each shower once a day in a bathroom that is not ventilated. Taking the heat of vaporization of water to be 2450 kJ/kg, determine the contribution of showers to the latent heat load of the air conditioner per day in summer?

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Maeve Reilly · Answer 1

Q = 2450 KJ/day

Explanation:

We are given;

The amount of moisture produced by a person while taking shower; m = 0.25 kg/person

Total number of persons in the family; N = 4

Latent heat of vaporization of water:

h_fg = 2450 KJ/kg

Since amount of moisture per person is 0.25kg per day, thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day

The formula for the amount of latent heat added to the space due to shower per day, is given as;

Q = m_total x h_fg

Plugging in the relevant values;

Q = 1 x 2450 = 2450 KJ/day