Ask Question
18 February, 05:47

The fuel mixer in a natural gas burner mixes methane (CH4) with air to form a combustible mixture at the outlet.

Determine the mass flow rates at the two inlets needed to produce 0.5 kg/s of an ideal combustion mixture at the outlet. Use data from the tables.

+3
Answers (1)
  1. 18 February, 07:26
    0
    The mass flow rate of CH₄ is 0.0275 kg/s and the mass flow rate of air is 0.4725 kg/s

    Explanation:

    The molar masses are equal to:

    MCH₄ = 16.043 kg/kmol

    MN₂ = 28.01 kg/kmol

    MO₂ = 32 kg/kmol

    MH₂O = 18.01 kg/kmol

    MCO₂ = 44.01 kg/kmol

    The combustion reaction is:

    CH₄ + a (O₂ + 3.76N₂) = CO₂ + 2H₂O + 3.76aN₂

    The O₂ balance is:

    a = 1 + 1 = 2

    CH₄ + 2 (O₂ + 3.76N₂) = CO₂ + 2H₂O + 7.52N₂

    The masses of the reactants are equal to:

    mCH₄ = nCH₄ * MCH₄ = 1 * 16.043 = 16.043 kg

    mO₂ = nO₂ * MO₂ = 2 * 32 = 64 kg

    mN₂ = nN₂ * MN₂ = 2 * 3.76 * 28.01 = 210.64 kg

    mtotal = 16.043 + 64 + 210.64 = 290.683 kg

    The masses fractions are equal to:

    mfCH₄ = 16.043/290.683 = 0.055

    mfO₂ = 64/290.683 = 0.22

    mfN₂ = 210.64/290.683 = 0.724

    The mass flow rates of the reactants are equal to:

    mfrCH₄ = 0.055 * 0.5 = 0.0275 kg/s

    mfrair = 0.5 - 0.0275 = 0.4725 kg/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The fuel mixer in a natural gas burner mixes methane (CH4) with air to form a combustible mixture at the outlet. Determine the mass flow ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers