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1 June, 11:05

What is the sum of a 6-term geometric series if the first term is 24 and the last term is 1,417,176?

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  1. 1 June, 11:32
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    First, we need to solve for the common ratio from the data given by using the equation.

    a (n) = a (1) r^ (n-1)

    1417176 = 24 r^ (6-1)

    59049 = r^5

    r = 9

    We can find the sum by the expression:

    S (n) = a (1) (1 - r^n) / 1-r

    where a (1) is the first term, r is the ratio and n is the number of terms.

    S (9) = 24 (1 - 9^6) / 1-9

    S (9) = 1594320
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