Solve by any method of your choosing.

1. y = x - 1 2. 3x - y = 8

2x + y = 5 y - 3x = - 2

Let us solve the first problem by substitution

y = x-1

2x + y = 5

substituting the value of y in equation 2,

2x + (x-1) = 5

= 2x + x = 5 + 1 = 6

3x = 6

thus, x = 6/3 = 2

Now, y = x - 1

= 2 - 1

=1.

Thus, x = 2, y = 1

Now for the second one:

3x - y = 8

y-3x = - 2

Thus, by eq. 2,

y = 3x - 2

Substituting the value of y in equation 1,

3x - (3x-2) = 8

= 3x - 3x = 10

thus, 0 = 10; which is a false statement

Thus, it has no solutions