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16 May, 03:19

A student wanted to estimate the number of chocolate chips in a commercial brand of cookie. he sampled 100 cookies and found an average of 10.5 chips per cookie. if we assume the standard deviation is 8, what is a 99% confidence interval for the average number of chips per cookie?

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  1. 16 May, 05:20
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    To find the interval we use the formula:

    x'+/-2.58σ/√n

    where:

    x' = sample mean=10.5

    2.58=table value at 99% confidence

    σ=population standard deviation=8

    n=100

    substituting the values we get:

    (10.5+/-2.58*0.08) / √100

    = (10.5+/-2.064) / 10

    = (10.5+2.064,10.5-2.064) / 100

    = (0.126, 0.084)
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