In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?

a) 242.4 in.

b) 265.3 in.

c) 308.3 in.

d) 324.1 in.

Question

Mathematics

Derick Salinas

12 February, 20:37

In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?

a) 242.4 in.

b) 265.3 in.

c) 308.3 in.

d) 324.1 in.

+3

Answers (1)

Know the Answer?

Malakai Watts · Answer 1

You need to use the Law of Cosines:

AC² = AB² + BC² - 2·AB·BC·cos (b)

Therefore, you get:

AC = √ (90² + 80² - 2·90·80·cos (50)

=√5243.86

= 72.4 in

Now you can sum up all the sides in order to find the perimeter:

AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

The correct answer is A) 242.4 in

In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?a) 242.4 in.b) 265.3 in.c) 308.3 in.d) 324.1 in.

In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?

a) 242.4 in.

b) 265.3 in.

c) 308.3 in.

d) 324.1 in.