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30 June, 13:28

The GCD (a, b) = 18, LCM (a, b) = 108. If a=36, find b.

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  1. 30 June, 15:41
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    The way to solve this is by using Venn diagrams with one circle as a (36) and the other as b (?). If a is 36, the factors of 36 are 3*3*2*2. If 18 is the greatest common divisor, that goes in the overlap of a and b. So if the factors of 18 are 3*3*2, the common ones between that and 36 are 3*3*2 which leaves a 2 alone in the a circle. The least common multiple is found by multiplying all the factors together of a, b and the overlap. If all the factors multiplied together equal 108, then 2 (from the a side all alone) * (3*3*2) from the overlap*x (in the b circle) = 108. Or in other words: 2*3*3*2*x=108 or 36x=108. If we solve for x we get that x=3. So b is the 18 in the overlap times 3, which is 54.
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