How do I solve the running time of a train between two terminals is 48 minutes, and there is a 7-minutes layover at each terminal. If a train leaves one terminal at 11:00 a. m. This train is due back at the same terminal at what time?

At First lets say the train is at terminal A

To get to terminal B (next terminal)

It takes him 48 minutes

Then spend 7 more minutes at terminal B

(48 + 7 = 55 minutes spent so far)

Then spend 48 more minutes from terminal B to go back to terminal A

(55 + 48 = 103 minutes spent)

Convert minute to hour (divide by 60)

103/60 = 1.7 h

11 + 1.7 = 12.7

So the time would be 7 minutes past 12

12:07 pm.