What is the cost of constructing a fence 6 and a half feet (6'6") high around a lot measuring 90 ft by 175 ft; if the cost of erecting the fence is $1.25 per linear ft and the cost of materials is $.825 per square ft?

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Mathematics

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6 April, 20:37

What is the cost of constructing a fence 6 and a half feet (6'6") high around a lot measuring 90 ft by 175 ft; if the cost of erecting the fence is $1.25 per linear ft and the cost of materials is $.825 per square ft?

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Blackjack · Answer 1

Based on the given values, I can only assume that the fence forms a rectangular shape. With this, the perimeter of the lot is:

Perimeter of lot = 2 * 90 + 2 * 175

Perimeter of lot = 180 + 350

Perimeter of lot = 530 feet

Since the cost per linear feet (perimeter) is $1.25, therefore the cost of erecting the fence is:

Cost of erecting fence = $1.25 * 530

Cost of erecting fence = $662.50

The area of the fence would be equal to the perimeter multiplied by the height:

Area of fence = 530 feet long * 6.5 feet high

Area of fence = 3445 square feet

Then the cost of materials will be:

Cost of materials = 3445 * $.825

Cost of materials = $2,842.13

Therefore the total cost would be:

Total cost = $662.50 + $2,842.13

Total cost = $3504.63