Express the complex number sqrt6 (cos315+isin325) in standard form

I think there is a mistake in the equation √6 (cos315+isin325)

where sin 325 should be sin 315, if so

1) the angle 315 is in the 4th quadrant, where cos is positive & sin, negative

cos 315 = cos (315-360) = - 45 and cos (-45) = √2/2 & sin (-45) = - √2/2

Then z = √6 (√2 / 2 - i√2 / 2)

z=√6 x √2 / 2 - √6 x √2 / 2) = √12 / 2 - i√12 / 2)

Simplify: z = √3 - i√3