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23 November, 14:09

Benjamin has $6000 invested in two accounts. One earns 8% interest per year, and the other pays 7.5% interest per year. If his total interest for the year is $472.50, how much is invested at 8%?

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  1. 23 November, 14:16
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    0.08x+0.075 (6000-x) = 472.5

    Solve for x

    0.08x+450-0.075x=472.5

    0.08x-0.075x=472.5-450

    0.005x=22.5

    X=22.5/0.005

    X=4500 invested at 8%
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