Ask Question
25 March, 21:10

Suppose you just received a shipment of twelve televisions. Two of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

+5
Answers (1)
  1. 26 March, 00:55
    0
    P (both work) = ((10-3) / 10) * ((10-3-1) / 9) = (7/10) * (6/9) = 42/90

    P (at least one does not work) = 1 - P (both work) = 1 - 42/90 = 48/90 = 24/45.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose you just received a shipment of twelve televisions. Two of the televisions are defective. If two televisions are randomly selected, ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers