Five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

Father = x

son = y

x-5 = 7 (y-5)

x + 5 = 3 (y+5) solve the system

x-5 = 7y-35

x+5 = 3y + 15

x-5 = 7y-35

-x-5 = - 3y - 15

-10 = 4y - 50

+50 + 50

40 = 4y

10 = y

Solve for X

x+5 = 3 (10) + 15

x+5 = 45

x = 40

The father is 40yrs old and the son is 10yrs old.