A rectangular photograph is mounted on a poster and has a two inch border on each side. The poster itself is mounted on a frame whose sides are the same length as the sides of the poster. The frame cost $2 per inch and the cost of the frame was $160. If the area of the photograph is 231 inches squared. What are the dimensions of the frame?

Let's define variables:

w: width of the photograph

l: length of the photograph

The cost of the box is:

2 * (2 * (w + 2)) + 2 * (2 * (l + 2)) = 160

The area is:

(w + 2) * (l + 2) = 231

Solving the system of equations we have:

w = 5 inches

l = 31 inches

Then, the dimensions of the frame are:

w + 2 = 7 inches

l + 2 = 33 inches

Answer:

the dimensions of the frame are:

7 inches * 33 inches