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14 December, 19:19

If f (x) = 2x^2-2-10 what is the value of f (1) to the nearest tenth of necessary

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  1. 14 December, 23:06
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    Wherever you see an x in the equation, simply sub in 1.

    f (1) = 2 (1) ² - 2 - 10

    = 2 - 2 - 10

    = - 10

    Therefore, the answer is - 10.
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