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22 July, 18:23

Item 12 a regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface area of 57 square centimeters. what is the surface area of the regular triangular pyramid?

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  1. 22 July, 18:49
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    Let SA = surface area, la=lateral area, b=base, h=height, l=slant height;

    b=l

    57=3 (1/2b²)

    57/3*2=b²

    b = √38

    SA = 1/2 (√38) ²+57 cm² = 94 cm²
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