An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by: h (x) = - 5x2+20x+60 what is the height of the object at the time of the launch (answer in meters)

The height of the object after x sec is modeled by:

h (x) = - 5x^2+20x+60

The height of the objct at the time it was launched will be given as follows:

when the object is launched, x=0.

hence the value of h will be:

h (0) = - 5 (0) ^2+20 (0) + 60

simplifying the above we get:

h (0) = 60

Answer: 50 m