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7 February, 14:25

What are the x-intercepts of the graph of the function f (x) = x2 + 5x - 36?

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  1. 7 February, 17:43
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    The x-intercept of a function is the value of x when y or f (x) is zero. It is like asking what are the roots of the given equation. Calculation is as follows:

    0 = x^2 + 5x - 36

    To solve this, we need to complete the square.

    36 = x^2 + 5x

    36 + 25/4 = x^2 + 5x + 25/4

    169/4 = (x + 5/2) ^2

    √169/4 = √ (x + 5/2) ^2

    √169/4 = x + 5/2

    x1 = 13/2 - 5/2 = 4

    x2 = - 13/2-5/2 = - 9
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