A box is launched upward from the ground at a speed of 57 feet per second. Calculate the height in feet of the box at 3 seconds. use g=32 ft/s^2 as the acceleration due to gravity

The vertical height traveled is given by

h = ut + - (1/2) g*t^2

where

u = 57 ft/s, initial speed

t = tme, s

g = 32 ft/s^2

After 3 seconds,

h = (57 ft/s) * (3 s) - (1/2) * (32 ft/s^2) * (3 s) ^2

= 171 - 144

= 27 ft

Answer: 27 ft