Given: ∆ABC, m∠C = 90° m∠BAC = 2m∠ABC BC = 24, AL - ∠ bisector Find: AL

Will be brainliest answer if right!

M∠BCA=90, then m∠BAC + ∠ABC=90

m∠BAC = 2m∠ABC, then 2m∠ABC + m∠ABC=90, m∠ABC=30, and m∠CAB=60

ΔBAC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2

AC:BC=1:√3, AC=BC/√3

BC=24, AC=24/√3=8√3, (you don't need AB, but AB=2AC=16√3)

AL bisects angle A = >m∠LAC=30

ΔALC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2

AC:AL=√3:2

AL=2AC/√3=2*8√3/√3=16