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15 June, 16:19

A rectangle poster covers an area of 380.16 square inches of a display board. The width of the poster is 12 inches less than its length. Find the width of the poster.

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  1. 15 June, 19:07
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    Let the width = x - 12

    the length = x

    we have this area equation: x (x-12) = 380.16

    =>x^2-12x-380.16=0

    => (5x-132) (5x+72) = 0

    =>x = 132/5 and x = - 72/5 (no)

    =>The width of the poster is: 132/5 - 12 = 72/5 inches
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