A rectangle has a length five more than twice the width. If the perimeter is 22 units find the width and length

Set the following: Length = L Width = W

The length is twice the width: L = 2*W or: W = L/2

Perimeter: P = 60ft = 2*L + 2*W

Substituting L for W in the perimeter equation gives:

P = 60ft = 2*L + 2 * (L/2) = 2*L + L = 3L

L = 60ft/3 = 20ft W=L/2=20ft/2=10ft

Verify result: Perimeter = P = 60ft = 2L + 2W = 2*20ft + 2*10ft = 40ft+20ft = 60ft

The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft) ^2

-Rosie