The sum of 5 consecutive integers is 205. What is the third number?

If 5 consecutive integers is 205,

then a + b + c + d + e = 205

but also, each integer is separated by a difference of 1

⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205

⇒ 5a + 10 = 205

⇒ 5a = 195

⇒ a = 39

∴ third term = 39 + 2

= 41