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22 July, 15:24

What is the following sum? Assume x>=0 and y>=0 square root x^2y^2+2 square root x^3y^4+xy square root y

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  1. 22 July, 16:06
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    To solve this problem you must apply the proccedure shown below:

    1. You have the following expression given in the problem above:

    x^2y^2+2√ (x^3y^4) + xy√y

    2. Therefore, you have:

    x^2y^2+2 (x^3y^4) ^1/2+xy (y) ^1/2

    3. By the exponents properties, you obtain:

    x^2y^2+2x^3/2y^4/2+xy^3/2

    x^2y^2+2x^3/2y^2+xy^3/2

    Therefore, as you can see, the answer is: x^2y^2+2x^3/2y^2+xy^3/2
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